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# PlayGround

$F_{pole} = \frac{1}{2} \times \rho \times C_d \times A_{wind} \times v_{wind}^2$

<x>F_{pole} = \frac{1}{2} \times \rho \times C_d \times A_{wind} \times v_{wind}^2</x>

<x>\rho</x> = Density of air = about 1.2 Kg/m³ <br /> <note warning>C_d = Coefficient of drag = 1.0 (cylinder Re > 100) <br /></note> <math2>A_{wind}[/itex] = Area of turbine = 4 m² <br /> <note tip><math2>v_{wind}[/itex] = Wind speed in m/s</note>

h_1=0.32 m d_1=0.32 m A_1=0.1024 m^2 h_2=0.48 m d_2=0.32 m A_2=0.1536 m^2

 2}[W] 2} [W] 2} [W] m/s km/h P_{wind_0.1024m P_{wind_0.1536m 1.8 6.5 0.35 0.5 4.5 16.00 5.5 8.2 6.25 22.50 15 22.6 8.0 29 32 48 m/s P_{wind_0.1024m P_{\rho=0.2} 1.8 0.35 0.07 4.5 5.5 1.1 6.25 15 3 8.0 32 6.4 m/s P_{wind_0.1536m P_{\rho=0.2} 1.8 0.5 0.1 4.5 8.2 1.65 6.25 22.6 4.5 8.0 48 9.6

Assuming a bad (20%) or decent (30%) turbine design \rho_{turbine}=0.26 A rather bad permanent magnet alternator with \rho_{alternator}=0.75; A normal synchronous rectifier with superb-by-design perfomance of \rho_{rect}=0.98; A buck-boost inverter with a good performance of \rho_{rect}=0.85; ⇒ \rho_{overall}=0.25*0.75*0.98*0.85=0.16

<references />

$\Rho_{simple drag turbine} = 20% \Rho_{decent} = 30% \Rho_{good} = 30% \Rho_{superb vawt} = 40%$