~~NOCACHE~~

====== PlayGround ======



{{:playground:chart.png?nolink|}}

<math>F_{pole} = \frac{1}{2} \times \rho \times C_d \times A_{wind} \times v_{wind}^2</math>

<x>F_{pole} = \frac{1}{2} \times \rho \times C_d \times A_{wind} \times v_{wind}^2</x>


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<x>\rho</x> = Density of air = about 1.2 Kg/m³ <br />
<note warning>C_d = Coefficient of drag = 1.0 (cylinder Re > 100) <br /></note>
<math2>A_{wind}</math> = Area of turbine = 4 m² <br />
<note tip><math2>v_{wind}</math> = Wind speed in m/s</note>

h_1=0.32 m
d_1=0.32 m
A_1=0.1024 m^2
h_2=0.48 m
d_2=0.32 m
A_2=0.1536 m^2
|m/s|km/h|P_{wind_0.1024m^2}[W]|P_{wind_0.1536m^2}[W]
|1.8|6.5|0.35|0.5|
|4.5|16.00|5.5|8.2|
|6.25|22.50|15|22.6|
|8.0|29|32|48|
|m/s|P_{wind_0.1024m^2} [W]|P_{\rho=0.2}|P_{\rho=0.3}
|1.8|0.35|0.07|0.1
|4.5|5.5|1.1|1.65
|6.25|15|3|4.5
|8.0|32|6.4|9.6
|m/s|P_{wind_0.1536m^2} [W]|P_{\rho=0.2}|P_{\rho=0.3}
|1.8|0.5||0.1|0.15
|4.5|8.2||1.65|2.5
|6.25|22.6||4.5|6.8
|8.0|48||9.6|14.4
Assuming a bad (20%) or decent (30%) turbine design \rho_{turbine}=0.26
A rather bad permanent magnet alternator with \rho_{alternator}=0.75;
A normal synchronous rectifier with superb-by-design perfomance of \rho_{rect}=0.98;
A buck-boost inverter with a good performance of \rho_{rect}=0.85;
=> \rho_{overall}=0.25*0.75*0.98*0.85=0.16


<references />

<math>
\Rho_{simple drag turbine} = 20%
\Rho_{decent} = 30%
\Rho_{good} = 30%
\Rho_{superb vawt} = 40%
</math>